Unformatted text preview: est statistic value:
− = √
At = 3.67 − 0
≈ 4.49
2.45
√9 = 0.05, the critical value(s):
± Powered by statisticsforbusinessiuba.blogspot.com =± ( ,) == ± (,. ) = ±2.306 Statistics for Business  Chapter 08: The Comparison of Two Populations Example I01: (Case of the Comparison of Two Population Means by using PairObservation) 5 International University IU PROBLEM I01B:
(Situation II) A study is undertaken to determine how consumers react to energy conservation efforts. A random group of 60 families is
chosen. Their consumption of electricity is monitored in a period before and a period after the families are offered certain
discounts to reduce their energy consumption. Both periods are the same length. The difference in electric consumption
between the period before and the period after the offer is recorded for each family. Then the average difference in
consumption and the standard deviation of the difference are computed. The results are = 0.2 kilowatt and sD = 1.0
kilowatt. At = 0.01, is there evidence to conclude that conservation efforts reduce consumption? SOLUTION: With = −
= 60, = 0.2, = 1.0, = 0.01 We assume that the population of score differences is normally distributed.
: : ≤ 0 >0 The test statistic value:
= − = √
At 0.2 − 0
≈ 1.5492
1.0
√60 = 0.01, the critical value:
= = 2.33 Thus, at 0.01 level of significance, we cannot reject
since
∈ [− , ]. It means that with the hypothesis testing we do
not have sufficient evidence to prove that conservation efforts reduce consumption. Powered by statisticsforbusinessiuba.blogspot.com Statistics for Business  Chapter 08: The Comparison of Two Populations Thus, at 0.05 level of significance, we can reject
since [− , ]. It means that based on the hypothesis testing we
have significant evidence to prove the differences between movie and commercial viewing. 6 International University IU COMPARISON OF TWO POPULATION MEANS
METHOD 02
COMPARISON OF TWO POPULATION MEANS USING INDEPENDENT RANDOM SAMPLES
HYPOTHESIS TESTING
PROCESS Two – tailed Testing Right – tailed Testing Left – tailed Testing Step 01
The populations are normally distributed
Or, the populations are assumed normal distribution
Assumptions
Step 02
: − =( − )
: − ≤( − )
:−
Determine the null and
alternative
hypotheses
: − ≠( − )
: − >( − )
:−
( and )
Step 03
Situation I:
Compute the test statistic Condition: and are known (for all and )
value ( / ) and the Method: We use −
and
= ( ⁄ )+( ⁄ )
critical value(s) ( / )
The test statistic value:
= ( ̅ − ̅ )−(
+ Powered by statisticsforbusinessiuba.blogspot.com − ) ≥( − ) <( − ) Statistics for Business  Chapter 08: The Comparison of Two Populations PART I 7 International University IU
At the level of significance, , the critical value(s):
=± = / =− Situation II: Condition: and are unknown
= ( and are believed to equal (although unknown)) Method: We use −
And,
=
= ( (1⁄ with
=(
+ 1⁄ ) with − 1) + (
( − 1) + ( − 1)
− 1) − 1) + ( ( − 1) ) The test statistic value:
= ( ̅ − ̅...
View
Full Document
 Winter '09
 Statistics, Normal Distribution, Null hypothesis, Statistical hypothesis testing, International University IU

Click to edit the document details