4 there are many ways to do this heres my favorite

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Unformatted text preview: st velocity is smaller than 1. (b) This is almost exactly the same, as the two events are spacelike separated we have ∆x2 > ∆t2 , (18) the equation we want to solve is now γ 1 v v 1 ∆t ∆x = 0 ∆¯ x , (19) ∆t the boost velocity is v = − ∆x , and we see by the spacelikeness condition that |v | < 1 implying a sensible boost. 4. There are many ways to do this. Here’s my favorite: take two meter sticks. On one of them attach two blue pens on the two ends of the sticks; on the other attach two red pens. Put the blue one in frame F and the red one in frame F ; but also set up a piece of paper so that as the meter sticks move the pens draw lines on the paper. In frame F we see the red meter stick moving while the blue one is at rest; thus if there is any contraction the red lines should be inside the blue lines on the paper. In frame F the blue stick is moving and the red one is at rest; thus if there is any contraction now the blue lines should be inside the red lines. These obviously can’t be true at the same time; thus there can be no co...
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This document was uploaded on 02/28/2014.

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