BCHE 395-11 2013 Enzymes Intro

Enzyme ackve sites are complimentary to the transikon

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Unformatted text preview: an link the rate constant k, to transi8on state ac8va8on energy, ΔG⧧: k= ⧧ kT e-ΔG /RT k à༎ Boltzmann constant h à༎ Planck’s constant h •  Take home: rate is inversely and exponen8ally propor8onal to ac8va8on energy •  So a lower ac8va8on energy means a faster rate reac8on 23 The Secret of Life •  For a molecule (e.g. substrate) to be stable, it must have a high acKvaKon energy for conversion to product (that’s what “stable” means…) even though equilibrium (thermodynamics) may hugely favor product •  So, to convert stable molecules (S) into other stable molecules (P) (even where equilibrium is unfavorable), requires selec8ve reduc8on of the ac8va8on energy – the job of enzymes 24 ReacKon Coordinate Diagram E + S ⇌ [ES ⇌ES⧧⇌EP] ⇌ E + P •  Energy is needed to get to the “TransiKon Sta...
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This note was uploaded on 03/02/2014 for the course BIOCHEMIST 395 taught by Professor Potenza during the Spring '14 term at NMSU.

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