MAT 140 exam 1.pdf - Southern New Hampshire University...

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4/19/2021 Southern New Hampshire University - Gradebook 2/29 Question Auto graded Grade: 1/1.0 A+ 100% . The y -intercept is Your response Correct response (0,3/4) (0,3/4) Auto graded Grade: 1/1.0 A+ 100% . The vertical asymptote is x = Your response Correct response 4 4 Auto graded Grade: 1/1.0 A+ 100% . Show your work and explain, in your own words, how you arrived at your answers. Answers with no relevant explanations may receive reduced or no credit.
4/19/2021 Southern New Hampshire University - Gradebook 3/29 Question 0 = x 2 − 2 x − 3 x − 4 For the x intercepts, substitute 0 for y and solve for x x 2 − 2 x − 3 = 0 Set numerator equal to zero and solve ( x − 3)( x + 1) = 0 Factor using AC method x − 3 = 0 x + 1 = 0 x=3,-1 x intercepts (3, 0), (−1, 0) y = ( 0 ) 2 − 2 0 − 3 ( 0 ) − 4 To find y intercepts substitute 0 in for x and solve for y y = 0 − 2 0 − 3 0 − 4 solve the equation y = 0 − 3 0 − 4 y = − 3 − 4 dividing two negative values results in a positive value y = 3 4 y intercepts 0, 3 4 x 2 − 2 x − 3 x − 4 find where expression is undefined to find verticle asymptote x = 4 Keywords: Partial Grades: Ungraded Grade: 0/1.0 F 0% Total grade: 1.0×1/5 + 1.0×1/5 + 1.0×1/5 + 1.0×1/5 + 0.0×1/5 = 20% + 20% + 20% + 20% + 0% Feedback: ( )
4/19/2021 Southern New Hampshire University - Gradebook 4/29 Question First we factor the numerator and denominator. f ( x ) = x 2 − 2 x − 3 x − 4 = ( x + 1 ) ( x − 3 ) ( x − 4 ) Next, we will find the intercepts. Evaluating the function at zero gives the y -intercept: f (0) = ( 0 + 1 ) ( 0 − 3 ) ( 0 − 4 ) = 3 4 To find the x -intercepts, we determine when the numerator of the function is zero. We now solve f ( x ) = ( x + 1)( x − 3) = 0 to get the x -intercepts at x = − 1 and x = 3. Thus we have a y -intercept at 0, 3 4 and x -intercepts at (−1, 0) and (3, 0). To find the vertical asymptotes, we determine when the denominator is equal to zero. This occurs when x + b = 0 and x − b = 0, giving us a vertical asymptote at x = 4. View Original Response Unfiltered Response ( )
4/19/2021 Southern New Hampshire University - Gradebook 5/29 Question Q2 0/0.0 0% Specify the domain of the function f ( x ) = 5 x + 35. The domain of f ( x ) is x Your response Correct response >= >= Auto graded Grade: 1/1.0 A+ 100% Your response Correct response -7 -7 Auto graded Grade: 1/1.0 A+ 100% Show your work and explain, in your own words, how you arrived at your answers. Answers with no relevant explanations may receive reduced or no credit. 5 x + 35 ≥ 0 set the radicand greater than or equal to zero to see where the expression is defined 5 x ≥ − 35 5 x 5 ( − 35 ) 5 x ( − 35 ) 5 x ≥ − 7 Domain is [−7, ∞) Keywords: Partial Grades: Ungraded Grade: 0/1.0 F 0%
4/19/2021 Southern New Hampshire University - Gradebook 6/29 Question Total grade: 1.0×1/3 + 1.0×1/3 + 0.0×1/3 = 33% + 33% + 0% Feedback: The original function f ( x ) = 5 x + 35 is one-to-one.

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