Unformatted text preview: al to u, they must lie on this line L. Since v is nonzero, the line L is given
by all the scalar multiples tv of v. (Vector equation of a line.) C EDRIC C HAUVE , FALL 2013 1 f a cu lty of sc ie nce
d ep ar tment of mathem atics Week Date Sections Part/ References MATH 895-4 Fall 2010
Course Schedule Topic/Sections MATH 232 A SSIGNMENT #2 Notes/Speaker from FS2009
So since w is another vector on this line, we must have w = sv for some scalar s. Now v · w = 0 since
v andSept 7are orthogonal. So 0 = v · w = v · (sv) = s(v · v) = s||v||2 . Now 0 = s||v||2 forces s = 0 s...
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