{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

1381109946_687__232a4 (2)

# 4 i5 i6 unlabelled linearly 34 6 a no b yes 34

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: endent. 3.4: 14. (x1 , x2 , x3 , x4 , x5 ) = r(1, 1, 0, 0, 0)+s(1, 0, −2, 1, 0)+ (a) linearly Comtet74 t(−1, 0, 21, 0, 1). II.1, II.2, II.3(a) linearly independent. (b) linearly independent. (c) linearly dependent. (d) linearly dependent. 3.4: D6. FFFTT 3 3.4: 20. 3 Labelled structures I 3.5: D1. The solution set of Handoutb is obtained by translating the solution space of Ax = 0. Ax = #1 (self study) 4 D3. The system II.6 consistent, because it Labelled structures II and there can be as many as 7 free variables and as few as 3. So the 28 II.4, II.5, is 3.5: is homogeneous, dimension of the solution space can be anything from 3 to 7. Combinatorial Combinatorial Asst #1 Due 3.55D4. Oct 5 TFTTFIII.1, III.2 parameters Parameters FS A.III 6 IV.1, are Multivariable general test it to check whether aij = aji for all i, j with 1 ≤ i, j ≤ n. (self-study) 3.6: D2.12 and (c)IV.2 symmetric, (b) and (d) are not. TheGFs (a) 3.6: D4. A is a zero matrix (of some size) 7 19 IV.3, IV.4 Analytic Methods −3 Complex...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online