269 n 18 816 18 n 3 3 p caught 1

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Unformatted text preview: elects 3 of the teddy bears for testing, what is the probability that the traveler will be caught? Do this problem using one of the new (named) distributions. Ans. This is hypergeometric distribution: N = 18 pop n = 3 samples k = 6 illegal P (caught) = 1 – P (not caught) = 1 ­ P ( x = 0) ȹ k ȹ ȹ N − k ȹ ȹ 6 ȹ ȹ 18 − 6 ȹ ȹ 6 ȹ ȹ 12 ȹ ȹ ȹ ȹ ȹ x ȹ ȹ n − x ȹ ȹ 0 ȹ ȹ 3 − 0 ȹ ȹ 0 ȹ ȹ 3 ȹ 1 * 220 ȹ ȹ ȹ ȹ ȹ ȹ ȹ ȹ ȹ Ⱥ = ȹ Ⱥ ȹ Ⱥ = ȹ Ⱥ ȹ Ⱥ = P (x = 0) = ȹ Ⱥ ȹ = 0.269 N ȹ 18 ȹ 816 ȹ ȹ ȹ 18 ȹ ȹ ȹ ȹ ȹ ȹ ȹ ȹ n ȹ ȹ 3 ȹ ȹ 3 ȹ ȹ Ⱥ ȹ Ⱥ ȹ Ⱥ P (caught) = 1 ­ 0.269 = 0.730 3/6 CEE 202 – Engineering Risk & Uncertainty Spring 2011 (Bond) Homework 6 Lots of Distributions 3) (30 points) Mechanical failures of a certai...
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