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CEE 202 Homework 7 solutions

# 049787068 1 0049787068 1 0149361205 095 0141893145

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Unformatted text preview: idents) P(Fatality’ | X accidents) = XC0 ·0.050 ·0.95X But XC0 is always 1, so we can just do 0.95X Best do this in Excel now X P(X) P(F'|X) P(F'|X) P(X) 0 0.049787068 1 0.049787068 1 0.149361205 0.95 0.141893145 2 0.224041808 0.9025 0.202197731 3 0.224041808 0.857375 0.192087845 4 0.168031356 0.81450625 0.136862589 5 0.100818813 0.773780938 0.078011676 6 0.050409407 0.735091891 0.037055546 7 0.021604031 0.698337296 0.015086901 8 0.008101512 0.663420431 0.005374708 9 0.002700504 0.63024941 0.001701991 10 0.000810151 0.598736939 0.000485067 1/6 CEE 202 – Engineering Risk & Uncertainty Spring 2011 (Bond) Homework 7 Distributions Aplenty 11 12 13 14 15 0.00022095 0.568800092 0.000125677 5.52376E ­05 0.540360088 2.98482E ­05 1.27471E ­05 0.513342083 6.54364E ­06 2.73153E ­06 0.487674979 1.3321E ­06 5.46306E ­07 0.46329123 2.53099E ­07...
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