You select a random sample of 100 sheets and the mean

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Unformatted text preview: paper produced. You select a random sample of 100 sheets, and the mean paper length is 10.998 inches. Construct a 95% and a 99% confidence interval estimate for the population mean paper length. Comment on the functioning of the At 99% confidence level, zα/2 = z.005 = 2.576 production process. Example 1 Interval Estimation A paper manufacturer has a production process that operates continuously throughout an entire production shift. The paper is expected to have a mean length of 11 inches, and the standard deviation of the length is 0.02 inches. At periodic intervals, a sample is selected to determine whether the mean paper length is still equal to 11 inches or whether something has gone wrong with the production process to change the length of the paper produced. You select a random sample of 100 sheets, and the mean paper length is 10.998 inches. Construct a 95% and a 99% confidence interval estimate for the population mean paper length. Comment on the functioning of the At 99% confidence level, zα/2 = z.005 = 2.576 production process. Interval estimate: x ± zα 2 σn .02 10.998 ± 2.576 0100 10.998 ± 0.005152 10.992848 ≤ µ ≤11.003152 Example 1 Interval Estimation A paper manufacturer has a production process that operates continuously throughout an entire production shift. The paper is expected to have a mean length of 11 inches, and the standard deviation of the length is 0.02 inches. At periodic intervals, a sample is selected to determine whether the mean paper length is still equal to 11 inches or whether something has gone wrong with the production process to change the length of the paper produced. You select a random sample of 100 sheets, and the mean paper length is 10.998 inches. Construct a 95% and a 99% confidence interval estimate for the population mean paper length. Comment on the functioning of the At 99% confidence level, zα/2 = z.005 = 2.576 production process. Interval estimate: x ± zα 2 σn .02 10.998 ± 2.576 0100 10.998 ± 0.005152 10.992848 ≤ µ ≤11.003152 With 99% confidence, we conclude that...
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