10.1 Mean sd Known

# Par would like is greater than par balls we to

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Unformatted text preview: .05 or pvalue<0.05 H0: μ1 – μ2 ≥ D0 Ha: μ1 – μ2 < D0 reject H0 if zSTAT < zα or p-value<α H0: μ1 – μ2 = D0 Ha: μ1 – μ2 ≠ D0 reject H0 if zSTAT < –zα/2 or zSTAT > zα/2 or if p-value<α Example Can we conclude with 95% confidence that the mean driving distance of Par balls is greater than Ace balls? Hypothesis Tests Par, Inc. is a manufacturer of golf p-value Approach: equipment and has developed a new golfReject has been-value <to ball that H0 if p designed 0.05 provide “extra distance.”6.484 zSTAT = Par would like to demonstrate that their new Par golf p-value: balls (are zSTAT) = P(zthe .484) superior to ≥ 6 comparable Pz≥ ball made 1 – their competitor,.05. Inc. = by P(z ≤ 6.484)< α= Ace, In a test of driving distance using a Therefore, reject H0. mechanical driving device, a sample of Par golf balls was compared with a sample of Ace golf balls. In a sample of 120 balls, the Par balls averaged 275 yards and in a sample of 80 balls, the Ace balls averaged 258 yards. Based on data from previous driving distance tests, the two population standard deviations are known with σPar = 15 yards and σAce = 20...
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## This document was uploaded on 03/05/2014.

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