10.1 Mean sd Known

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Unformatted text preview: yards. test statistic upper tail test lower tail test twotailed test Difference Between 2 Population Means ( x Par - x Ace ) - D0 z STAT = s Par 2 s Ace 2 n Par + n Ace = 6.484 H0: DPar–Ace ≤ 0 Ha: DPar–Ace &gt; 0 reject H0 if zSTAT &gt; z.05 or pvalue&lt;0.05 H0: μ1 – μ2 ≥ D0 Ha: μ1 – μ2 &lt; D0 reject H0 if zSTAT &lt; zα or p-value&lt;α H0: μ1 – μ2 = D0 Ha: μ1 – μ2 ≠ D0 reject H0 if zSTAT &lt; –zα/2 or zSTAT &gt; zα/2 or if p-value&lt;α Example Can we conclude with 95% confidence that the mean driving distance of Par balls is greater than Ace balls? Based on p-value and critical Par, Inc.approaches, we can value is a manufacturer of golf equipment and has developed a new reject H0 that the mean golf ball that has been designed to driving distance for Ace balls provide “extra distance.” Par would like is greater than Par balls. We to demonstrate that their new Par golf balls an conclude the comparable c are superior to that the mean ball driving distance of Par balls made by their competitor, Ace, Inc. In a test of driving distance using a is greater than Ace balls. mechanical driving device, a sample of Hypothesis Tests Par golf balls was compared with a sample of Ace golf balls. In a sample of 120 balls, the Par balls averaged 275 yards and in a sample of 80 balls, the Ace balls averaged 258 yards. Based on data from previous driving distance tests, the two population standard deviations are known with σPar = 15 yards and σAce = 20...
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