10.4 Proportions

# 557 zstat households aware of the h0 p1 p2 0

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Unformatted text preview: statistic: Calculating z H0: p1 – p2 ≤ 0 campaign showed 120 out of 1. calculate upper Ha: p1 – p2 > 0 250Decision “aware” of the households pooled estimate: Rule: tail test client’s product. n1 p1 + n 2 p2 n After pAfter + n Before pBeforereject H0 if zSTAT > zα Reject = 0 if zSTAT z pH Before the new campaign = > n α + n n1 + n 2 After Before H0: p1 – p2 ≥ 0 began, a telephone survey of lower tail Ha: p1 – p2 < 0 150Statistical Decision: .4 = 0.45 households in 250×.48 + 150× the test = test reject H0 if zSTAT ≤ –zα zSTAT250 1150 = + .557 m2. arket area showed 60 calculate zSTAT: households zα = z.05 = 1.645 “aware” of the H0: p1 – p2 = 0 twopB .40 - .48 client’s product.efore - pAfter zSTAT = = < zα and tailed 1.557 Ha: p1 – p2 ≠ 0 =Therefore,1 using .45 STAT 1 1 Can we conclude z+ 1 ) a .05 (1 - .45)( 150 + 250 ) reject H0 if zSTAT ≤ – p(1 - p)( n n test zα/2 or if zSTAT > zα/2 H0 is that rejected. level of significance not the proportion of households aware Before After Example Do the da...
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## This document was uploaded on 03/05/2014.

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