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Unformatted text preview: statistic:
Calculating z
H0: p1 – p2 ≤ 0
campaign showed 120 out of
1.
calculate
upper
Ha: p1 – p2 > 0
250Decision “aware” of the
households pooled estimate:
Rule:
tail test
client’s product.
n1 p1 + n 2 p2 n After pAfter + n Before pBeforereject H0 if zSTAT > zα
Reject = 0 if zSTAT z
pH
Before the new campaign = > n α + n
n1 + n 2
After
Before
H0: p1 – p2 ≥ 0
began, a telephone survey of
lower tail
Ha: p1 – p2 < 0
150Statistical Decision: .4 = 0.45
households in 250×.48 + 150×
the test
=
test reject H0 if zSTAT ≤ –zα
zSTAT250 1150
= + .557
m2.
arket area showed 60
calculate zSTAT:
households zα = z.05 = 1.645
“aware” of the
H0: p1 – p2 = 0
twopB
.40  .48
client’s product.efore  pAfter
zSTAT =
= < zα and tailed 1.557 Ha: p1 – p2 ≠ 0
=Therefore,1 using .45
STAT
1
1
Can we conclude z+ 1 ) a .05 (1  .45)( 150 + 250 )
reject H0 if zSTAT ≤ –
p(1  p)( n
n
test zα/2 or if zSTAT > zα/2
H0 is that rejected.
level of significance not the
proportion of households aware
Before After Example Do the da...
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 Spring '13

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