Unformatted text preview: 14/-2.64 = -0.4318.
Figure 1: PART B
In this part of the lab, we have made a circuit shown in figure 2. We have adjusted the
potentiometer so that ICQ is 0.3mA or 0.1mA. With these conditions, the results are shown in
the figure 3 and 4. Just like part A, gain is solved by dividing delta y by delta x. Hand
calculation results are shown in figure 4 as well. enerator Load Inverters
the same IC chip asName:elShuvrasPodder re
n-chann devices, everal mo
nerator load” inverter uses a p-channel So, Lucas Tanaka
Partners: Jin device biased to
View Full Document
This document was uploaded on 03/07/2014 for the course EE 416 at Penn State.
- Fall '08
- Integrated Circuit