problem21_73

University Physics with Modern Physics with Mastering Physics (11th Edition)

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21.73: a) g 2.30 ) mol g mol)(22.99 100 . 0 ( m NaCl mol 100 . 0 Na = = g 3.55 ) mol g mol)(35.45 100 . 0 ( m Cl = = Also the number of ions is 22 A 10 02 . 6 mol) 100 . 0 ( × = N so the charge is: C. 9630 C) 10 60 . 1 )( 10 02 . 6 ( 19 22 = × × = - q The force between two such charges is: N. 10 09 . 2 m) 0200 . 0 ( ) 9630 ( 4 1 4 1 21 2 2 0 2 2 0 × = = = πε r q πε F b) . s m 10 89 . 5 ) kg 10 (3.55 N) 10 09 .
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Unformatted text preview: 2 ( / 2 23 3 21 = = =-m F a c) With such a large force between them, it does not seem reasonable to think the sodium and chlorine ions could be separated in this way....
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