problem21_71

University Physics with Modern Physics with Mastering Physics (11th Edition)

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21.71: a) b) Using the same force analysis as in problem 21.70, we find: θ mg d πε q tan 4 2 0 2 = and = ° ° = = q πε q d ) s m 80 . 9 )( kg 015 . 0 ( 25 tan ) 25 sin ) 2 . 1 ( 2 ( 4 (1.2)sin25 2 2 2 0 C. 10 79 . 2 6 - × c) From Problem 21.70, . tan 2 2 d kq θ mg = θ θ L mg kq θ L d θ 2 2 2 2 -6 2 9 2 2 2 sin ) s m kg)(9.8 015 . 0 ( m) 6 . 0 ( 4 C) 10 )(2.79 C Nm
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