Unformatted text preview: receive the small object. The total response time is 2 RTTo + RTT1 + RTT2 + + RTTn
b. RTT1 + + RTTn + 2 RTTo + 8 ⋅ 2 RTTo = 18RTTo + RTT1 + + RTTn .
c. RTT1 + + RTTn + 2 RTTo + 2 ⋅ 2 RTTo = 6 RTTo + RTT1 + + RTTn .
d. RTT1 + + RTTn + 2 RTTo + RTTo = 3RTTo + RTT1 + + RTTn . Problem 2: (20 Points) Consider the scenario shown in Figure 1 in which a server is connected to a router by a 100Mbps link with a 50ms propagation delay. Initially this router is also connected to two routers, each over a 25Mbps link with a 200ms propagation delay. A 1Gbps link connects a host and a cache (if present) to each of these routers and we assume that this link has 0 propagation delay. All packets in the network are 20,000 bits long. ECE374: Homework 2...
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- Spring '08
- Transmission Control Protocol, HTTP