Unformatted text preview: greater than dtrans. At time t=dtrans, where is the first bit of the packet? f. Suppose dprop is less than dtrans. At time t=dtrans, where is the first bit of the packet? g. Suppose s=2.5*108, L=500 bits, and R=128 kbps. Find the distance m so that dprop equals dtrans. Solution: d prop = m / s
a. seconds. d trans = L / R seconds. b. c.
d.
e.
f.
g. d end −to−end = ( m / s + L / R ) seconds. The bit is just leaving Host A. The first bit is in the link and has not reached Host B. The first bit has reached Host B. Want L
500
m= s=
2.5 × 108 ) = 977 km. 3(
R
128 × 10 Problem 3 (15 Points): A packet switch receives a packet and det...
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 Spring '08
 GANZ
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