N2 04096 say want to nd frequency of peak component

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Unformatted text preview: be a power of 2 >= signal length – so, set DFT length N to be N = 213 = 8192 magnitude of 8192- point DFT of sampled ‘boo’ PosiOve frequency part of DFT – k = 0,...,(N/2) = 0,...,4096...
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This test prep was uploaded on 03/06/2014 for the course ECE 563 taught by Professor Goeckel during the Fall '11 term at UMass (Amherst).

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