Otherwise we continue until the end 1 41 v0 6 6 2 58

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Unformatted text preview: x]. Doing the integrals and a little algebra gives U ( x + (1 y )) U (y ) (U (x) U (y )) which after a little more algebra is (6.18). Some concrete examples of utility functions are: Up (x) = xp /p with 0 < p < 1 for x 0 and U (x) = U0 (x) = ln x for x > 0 and U (x) = 1 for x 0. Up (x) = xp /p with p < 0 for x 0 and U (x) = 1 for x < 0. 1 for x 0. 0 00 Dividing by p is useful here because in all three cases Up (x) = xp 1 and Up (x) = p2 (p 1)x 0 for x 0. The second half of the definition is forced on us. In 0 the second and third cases Up (x) ! 1 as x # 0, while in the first Up (x) ! +1 as x # 0. An optimal investment problem. Given a utility function U and an initial wealth, find an admissible trading strategy n to maximize EU (WN ), where the wealth Wn satisfies the recursion (6.14) Wn+1 = n Sn+1 + (1 + r)(Wn n Sn ) Example 6.6. Consider now the concrete example of maximizing U (x) = ln x for a two-period binomial model with S0 = 4, u = 2, d = 1/2, and r = 1/4 where the probability of up and down are 2/3 and 1/3 respectively. Note that we are optimizing under the real...
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This document was uploaded on 03/06/2014 for the course MATH 4740 at Cornell University (Engineering School).

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