{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# set9 - The solu)on for electrons and proton will be done in...

This preview shows pages 1–5. Sign up to view the full content.

The solu)on for electrons and proton will be done in steps H e ψ r e ; r p 1 , r p 1 ( ) = E e r p 1 , r p 2 ( ) r e ; r p 1 , r p 1 ( ) 1. 2. H p p r p 1 , r p 2 ( ) = 2 2 m p p 1 2 + p 2 2 ( ) + e 2 4 πε 0 R 12 + E e r p 1 , r p 2 ( ) p r p 1 , r p 2 ( ) = E p r p 1 , r p 2 ( ) An now to solve the wave func)on of the nuclei moving in an eFec)ve poten)al We have done that… U r p 1 , r p 2 ( ) = e 2 4 0 R 12 + E e r p 1 , r p 2 ( )

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Diatomic molecules A simple picture: two balls connected by a spring U(r) r D
Harmonic oscillator U(r) r D Near the minimum the poten±al energy can be approximated by a parbola U ( r ) U r min ( ) + dU dr r = r min r r min ( ) + 1 2 d 2 U dr 2 r = r min r r min ( ) 2 The firste derivative is zero at the minimum U r ( ) U r min ( ) + 1 2 d 2 U dr 2 r = r min r r min ( ) 2 The value of the potential is a constant, that for the moment we do not care about U r ( ) k 2 r r min ( ) 2 r min

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Classical spring A: amplitude ; k: force constant ; m: mass ; ω: frequency Energy E = 1 2 mv 2 + 1 2 kx 2 Newton Eq.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 13

set9 - The solu)on for electrons and proton will be done in...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online