In a constant field electron current relaonships hole

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Unformatted text preview: * E x = µ p E x mp vx = − px q tn = − * Ex * nmn mn qtp p vx = x * = * E x pm p m p vx = 6 Electron Current in a Constant Field q tn nq 2 tn J x = −qn vx = qn ∗ Ex = Ex = σ n Ex = qnµn Ex ∗ mn mn ampere coulomb electrons cm = • • 2 3 electron s cm cm Electron Conductivity: σ n = qnµn q tn Electron Mobility: µn ≡ * mn 7 Hole Current in a Constant Field J x = qp vx = qp qtp Ex = pq 2 t p Ex = σ p Ex = qpµ p Ex m∗ m∗ p p ampere coulomb holes cm = • • 2 3 hole s cm cm Hole Conductivity: σ p = qpµ p qtp Hole Mobility: µ p ≡ * mp 8 Electron and Hole Current in a Constant Field Electron Current Rela.onships Hole Current Rela.onships J x,n = −qn vx = qnµn Ex = σ n Ex J x, p = qp vx = qpµ p Ex = σ p Ex Electron Conductivity: σ n = qnµn Hole Conductivity: σ p = qpµ p q tn Electron Mobility: µn ≡ * mn qtp Hole Mobility: µ p ≡ * mp Combined Current J x,total = q(nµn + pµ p )Ex = σ Ex σ = q(nµn + pµ p ) 1 V = IR, or I = V R We’ve made it to V=IR! 9 Density State Effec[ve Mass vs Conduc[vity Effec[ve Mass •  Ensure that the correct effec[v...
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