Homework 2 biochem

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Unformatted text preview: eq for the sum of the two reactions: Glucose 1-phosphate ——> Fructose 6-phosphate. G’º for both reactions can be found the the Biochemistry book Table 13.4. ln k"eq = -G'/RT = -(-5.6kJ/mol)/(2.48 kJ/mol) = 2.3 Keq = 10 5. (15%) Effect of [ATP]/[ADP] Ratio on Free Energy of Hydrolysis of ATP. Plot G against ln Q (mass-action ratio) at 25 ºC for the concentrations of ATP/ADP and Pi from the table indicated below. Gº for the reaction is -30.5 kJ/mol. Use the resulting plot to explain why metabolism is regulated to keep the ratio [ATP]/[ADP] high. (plot separately uploaded) ln Q 1 = ln [(2 x 10^-4)(1 x 10 ^-2)/(5 x 10^-3)] = -7.8 ln Q2 = ln [(2.2 x 10 ^-3)(1.21 x 10 ^-2)/(3 x 10 ^-3)] = -4.7 ln Q3 = ln [(4.2 x 10^-3)(1.41 x 10^-2)/(1x10^-3)] = -2.8 ln Q4 = ln [(5 x 10^-3)(1.49 x 10 ^-2)/(2 x 10 ^-4)] = -1.0 ln Q5 = ln[(2.5 x 10^-2)(1 x 10^-2)(5x10^-3)] = -3.0 G1 = G2 = G3 = G4 = G5 = The G for ATP hydrolysis is smaller wen [ATP/ADP] is low (<1) than when [ATP]/[ADP] is high. The energy available to a...
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This document was uploaded on 03/06/2014.

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