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Unformatted text preview: ceiling of the occupied room is also plaster. The other room is a mechanical equipment room, in which there is a standing noise level of 75 dB. What is the noise level going to be in the occupied room as a result of noise transmitted from the mechanical equipment room? a = 20'*30'*0.00+20'*30'*0.05+(20'*12'*2+30'*12'*2)*0.05 = 90 sabins NR = TL + 10 log(a 2 /S) NR is the Noise reduction, TL is the barrier transmission loss, in dB a 2 is the total absorption of the receiving room, in sabins S, Area of barrier wall, ft 2 NR = 33 +10 log (90/(20'*12')) = 28.74 dB IL new = 75 - 28.74 = 46.26 dB. Is that annoying? It's actually OK. Name three things that could be done to improve the situation, and calculate the results of doing one of them. A. Use another building construction to increase TL, such as #27, TL=59 dB B. Increase a 2 C. Increase a 1 . D. Reduce the contact of the two rooms....
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This homework help was uploaded on 02/20/2008 for the course ARCH 315 taught by Professor Schiler during the Spring '06 term at USC.
- Spring '06