{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}


0347 750000 50000 e 00347t t 78 hrs b e rtzf

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 0000 e ^(0.0347*t) T = 78 hrs B. E = (RT/zF) * ln ([ion outside cell]/[ion inside cell]) = ((8.314 J/K mol) * (273+37)K)/(1*96485 C/mol) * ln(0.145M/0.010M) = 0.0714 J/C = 0.0714 V C. If you have higher concentration of X on the inside and lower concentration on X on the want outside and you want to send the X from outside to inside against the concentration gradient, use Na+/K+ ATPase using ATP as energy source to drive Na+ out of the cell, so as the concentration of Na+ increases outside, it can come back in using the Na+/X cocowith transporter, with which the X comes back in. NAME: NAME: SID: 2. The small-molecule second messenger cyclic adenosine monophosphate (cAMP) plays a central role in several signal transduction pathways. Perhaps the best known function of cAMP is to bind and activate protein kinase A (PKA), which can phosphorylate proteins and trigger a variety of cellular effects. A. Suppose you conduct an equilibrium dialysis experiment that yields the fraction of bound PKA (r) as a function of cAMP concentration. Describe how you could extract the dissociation constant (Kd) from these data using Scatchard analysis. Your answer should include both an equation (which you do not need to derive) and a plot in which the value of Kd is related to the slope of the plot. (5) B. Suppose the Kd for the binding interaction between cAMP and PKA is 50 nM. What concentration of cAMP would you need to have in solution to occupy 75% of the binding sites on PKA? (10) A. PKA + cAMP PKA-cAMP (Kr backward and Kf forward) Kd = [PKA][cAMP]/[PKA-cAMP] = Kr/Kf Ka = 1/Kd R = [cAMP]/(Kd + [cAMP]) Need to include final equation of: r/[L] = 1/Kd - r/Kd Plot should include r/[L] on y axis (1/mM) and r on x axis; slope = -1/kd B. B. Kd = 50nM R = [cAMP]/(Kd + [cAMP]) 0.75 = x/(50+x) 0.75 * (50 + x) = x [cAMP] = 150 nM. 37.50 + 0.75x = x 150 NAME: NAME: SID: 3. Imagine you are performing mechanical testing on a polymeric biomaterial under consideration for use in a new type of catheter. A. Suppose you perform a...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online