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J09Chem1063exam3J09 - Chem 1063 Exam 3 J-Term 2009 Name I...

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Chem 1063 Exam 3. J-Term 2009 Name__________________________ I have neither given nor received unauthorized aid on this exam. You must show all work for credit. REMEMBER: Colligative properties depend on the concentration of DISSOLVED PARTICLES!!!!!!!!! Useful information: R= 8.317J/molK, 0.0821 L•atm/mol•K, ln P 1 P 2 = H vap R 1 T 2 1 T 1 , solu- bility = kP, P so ln = Χ A P A o + Χ B P B o , T b = K b m , T f = K f m , Π = MRT (1)(4 points) A major component of mothballs is napthalene. You can smell napthalene because it has a significant vapor pressure at room temperature. You can use the Clausius-Claperyon equation to calculate this vapor pressure. Napthalene has a normal boiling point of 218 ºC and a H of 62 kJ/mol. What is the vapor pressure of napthalene at 25 ºC? (2)(4 points) At 100 feet, the external pressure on a scuba diver is 3.95 atm. If the mole fraction of N 2 in the breathing gas is 0.8, and the Henry’s Law constant is 6.1 x 10 -4 M/ atm for nitrogen, what is the maximum concentration of nitrogen in the blood of a diver at 100 ft?
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(3)(4 points) You need to heat a reaction at a constant 105 ºC.
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