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Unformatted text preview: the corresponding physical characteristic.
4π 2
b. Starting with Newton’s version of Kepler’s 3rd Law ( P 2 =
a3
G ( m1 + m2 )
[equation 2.37]), derive the relationship between orbital period of a “low
orbit” and this physical characteristic from part (a) assuming a “low orbit”
essentially has an semimajor axis equal to the planet’s radius and the
satellite has much lower mass than the planet.
c. Given your derivation in part (b), should a low Jovian orbit around Jupiter
have a period higher or lower than 90 minutes. Appendix C Table 1: Planetary Physical Data from Carroll and Ostlie
Equatorial
Sidereal
Mass
Average Density
Radius
Rotation Period
Planet
(M⊕)
(kg m3)
(R ⊕ )
(days)
Mercury
0.055
0.383
5427
58.6462
Venus
0.815
0.949
5243
243.018
Earth
1.000
1.000
5515
0.997271
Mars
0.107
0.533
3933
1.02596
Jupiter
317.83
11.209
1326
0.4135
Saturn
95.159
9.449
687
0.4438
Uranus
14.536
4.007
1270
0.7183
Neptune
17.147
3.883
1638
0.6713
Pluto (dwarf planet)
0.002
0.178
2110
6.3872
Eris (dwarf planet) 0.002 0.188 – Page 2 of 2 – 2100?...
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 Spring '14
 Dr.JuanCabanela

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