0 0 24r cos 2 r drd 6 f x y fx i fy j

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Unformatted text preview: ion x = 2u, y = 3v . Simplify it, we end up with 36u2 + 36v 2 = 36 ⇒ 5 u2 + v 2 = 1 Therefore, the original integral can be written into x2 dA = (2u)2 (6) dudv = 24u2 dudv u2 + v 2 ≤ 1 R u2 + v 2 ≤ 1 Using the polar coordinates, we have 2π 1 (...
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This document was uploaded on 03/08/2014.

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