homework solutions7

Rn 6 222 86 218 84 po 4he 2 rn 6 206 82 pb a 16

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Unformatted text preview: 206 82 Pb ΔA = 16 Y 4α decays 4α decays Y ΔZ = 8 since actual ΔZ = 4 Y # β- decays = 8 -4 = 4 Homework Solutions for Chem 481 Chapter 2 243 17 9 F - N/Z < 1, so you expect β+ decay (instead of EC) for this value of A c) 49 20 Ca - N/Z > 1, so you expect β- decay d) 9. a) b) 8. 181 225 89 Ac 6 Am - you expect α decay, with possible competition from SF, because of large A Ir - N/Z ~ 1.35, so this is n-deficient for this mass number; expect EC decay 221 87 Fr + 4He 2 Q = 931.5 MeV/amu [MAc-225 - MFr-221 - MHe-4] Q...
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