lecture notes10

339 pbso4pb b ee v 0355 write the line notation for

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PbSO4/Pb b) EE (V) -0.355 Write the line notation for this cell. Pb(s) c) Since the Cu2+ reduction is spontaneous (EE>0), but the Pb2+ reduction is not, oxidation of the Pb must occur. Electrode 2 is the anode. PbSO4(s) SO42-(0.115 M) Cu2+ (0.0300 M) Cu(s) Calculate the voltage (E) for this cell. Ecell = Eox + Ered anode: Pb(s) + SO42-(aq) X PbSO4(s) + 2e- cathode: Cu2+(aq) + 2e- X Cu (s) Ecell = 0.327 V + 0.294 V = 0.621 V 0.621 V...
View Full Document

This document was uploaded on 03/06/2014 for the course CHEM 321 at CSU Northridge.

Ask a homework question - tutors are online