Quiz06_13solutions

5m2 1kg 05m 245m s 2 c the velocity of the

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Unformatted text preview: 0.5m)2 = 6.125J = 6.13J 2 2 (b) Mechanical energy is conserved here: 1 1 Eel = Ek , k Δx 2 = mv 2 2 2 Centripetal acceleration is: a = v 2 / R Then a = k Δx 2 / m / R = (49 N / m)(0.5m)2 / (1kg ) / (0.5m) = 24.5m / s 2 (c) The velocity of the ball at highest point is 0. Mechanical energy is conserved here: 1 k Δx 2 = mgh 2 Then h = k Δx 2 / 2mg = (49 N / m)(0.5m) 2 / 2 / (1kg ) / (9.8m / s 2 ) = 0.625m Ek = E p , Physics 221 Quiz 6 Name & Section...
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This document was uploaded on 03/12/2014 for the course PHYS 221 at Iowa State.

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