Quiz09_13solutions

0 40 2 24 kg m 2 2 2 2 i i cm md 2 where i

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Unformatted text preview: 3 L 1 ! F2 L = mL2! , or 2 3 != 3( F1 ! 2 F2 ) 3[ 6.0 ! 2(9.0 )] = = !6.0 rad/s2 . 2 mL 2(2.0 )(1.5) This is negative, so the acceleration is CW, and the acceleration vector points into the page. Physics 221 Quiz 9 Spring 2013 Name Section___________ Quiz 9D 1.) Find the moment of inertia of a solid cylinder, mass M = 1.0 kg and radius R = 4.0 m, rotating about an axis along the edge of the cylinder (as shown). (Use ICM = (1/2) MR2 for rotation of a solid cylinder about an axis through its center.) Solu...
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This document was uploaded on 03/12/2014 for the course PHYS 221 at Iowa State.

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