Unformatted text preview: a solid cylinder, mass M = 3.0 kg and radius R = 2.0 m, rotating about an axis along the edge of the cylinder (as shown). (Use ICM = (1/2) MR2 for rotation of a solid cylinder about an axis through its center.) Solution: Using the parallel axis theorem, the moment of inertia of the cylinder about the axis along its side is I = I CM + Md 2 , where I CM = I= 1
MR 2 and d =R, so
2 1
3
3
MR 2 + MR 2 = MR 2 = (3.0 )(2.0 )2 = 18 kgm 2 . 2
2
2 2.) A rod, with L = 1.5 m and m = 2.0 kg, can rotate about its end around an axis O perpendicular to the page (as shown). Force F1 = 6.0 N acts at L/2 and force F2 = 9.0 N acts at L. What is the angular acceleration of the rod? (Use ICM = (1/3)mL2 for a rod rotating about an axis through the end and perpendicular to the rod.) Solution: Using ! net = I" = F1 12
mL " , and with CCW torque defined as positive,...
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This document was uploaded on 03/12/2014 for the course PHYS 221 at Iowa State.
 Spring '08
 HerreraSiklody
 Mass

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