Quiz08_13solutions

E m1v1m1m2v2 during sliding the change in kinetic

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Unformatted text preview: speed of the clay immediately before impact? Solution: During impact, momentum of the clay ­block system is conserved i.e.: m1V1=(m1+m2)V2 During sliding, the change in kinetic energy of the clay ­block ­surface system is equal to the increase in the internal energy: 1 ! ! + !! !! = !! ! = ! !! + !! !" 2! 1 ! ! 0.112!" !! = 0.650 0.112!" 9.80 ! 0.075! 2 ! ! ! !! = 0.956 ! ! ! =>  !! = 0.977 ! ! 12.0×10!! !" !! = 0.112!" 0.977 ! ! =>  !! = 9.12 ! !...
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