Unformatted text preview: be found from the ideal gas law. 3RT
vrms ( N 2 ) =
⇒ M 2
Mvrms
RT =
3 PV = nRT ⇒ 2 −3
2
nRT nMvrms (1300mol ) ( 28 ⋅10 kg / mol ) (386m / s )
P=
=
=
= 2.1⋅105 Pa = 2.1atm 3
V
3V
3 ⋅ (8.5m ) P = 2.1atm 2) The air in a cylinder is compressed adiabatically to 1/5 of its initial volume. Determine the initial pressure if the final pressure of air is 4.00 MPa. Treat air as an ideal gas with γ = 1.40. Solution: !! ! = !"#$%&#%...
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This document was uploaded on 03/12/2014 for the course PHYS 221 at Iowa State.
 Spring '08
 HerreraSiklody
 Mass

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