Quiz14_13solutions

5m3 3rt 3pv vrms n 2 386m s m nm 1300mol

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: RT = PV n 3 ⋅ ( 2.1atm ) (1.013 ⋅105 Pa / atm ) (8.5m3 ) 3RT 3PV vrms ( N 2 ) = = = = 386m / s . M nM (1300mol ) ( 28 ⋅10−3 kg / mol ) v rms (N 2 ) = 3.9 ⋅ 10 2 m / s 2) The air in a cylinder is compressed adiabatically to 0.45 of its initial volume. Find the ratio of its initial and final pressure. Treat air as an ideal gas with γ = 1.40 Solution: In an adiabatic process, !! ! = !"#$%&#% ! ! !! ! = !! !  ! ! ! !! =  ! !! ! !! =  !.!"! !.!" ! = 0.45 !.!" = 0.33 Physics 221 Spring 2013...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online