Unformatted text preview: ar singular point. ________________________________________________________________________
page 211 —————————————————————————— CHAPTER 5. ——
Section 5.5
1. Substitution of The roots are results in the quadratic equation , 3. Substitution of The root is , is results in the quadratic equation , where , with multiplicity two . Hence the general solution, for 5. Substitution of The root is . Hence the general solution, for , where results in the quadratic equation , is , where , with multiplicity two . Hence the general solution, for 6. Substitution of The roots are 7. Substitution of The roots are 8. Substitution of results in the quadratic equation , . Hence the general solution, for , where , is results in the quadratic equation . Hence the general solution, for results in the quadratic equation , is , where , is , where ________________________________________________________________________
page 212 —————————————————————————— CHAPTER 5. —— The roots are complex, with . Hence the general solution, for , is 10. Substitution of results in the quadratic equation The roots are complex, with 11. Substitution of . Hence the general solution, for results in the quadratic equation The roots are complex, with , where , is , where . Hence the general solution, for , is 12. Substitution of The roots are 14. Substitution of results in the quadratic equation , . Hence the general solution, for , where , is results in the quadratic equation The roots are complex, with
, is , where . Hence the general solution, for Invoking the initial conditions, we obtain the system of equations ________________________________________________________________________
page 213 —————————————————————————— CHAPTER 5. —— Hence the solution of the initial value problem is As , the solution decreases without bound. 15. Substitution of The root is results in the quadratic equation , where , with multiplicity two . Hence the general solution, for , is Invoking the initial conditions, we obtain the system of equations Hence the solution of the initial value problem is ________________________________________________________________________
page 214 —————————————————————————— CHAPTER 5. —— We find that
18.
36 as . Substitution of results in the quadratic equation . The roots are .
If
, the roots are complex, with
solution, for
, is . Hence the general Since the trigonometric factors are bounded,
are equal, and Since lim , as as . If . If , the roots , the roots are real, with . Hence the general solution, for Evidently, solutions approach zero as long as , is That is,
. Hence all solutions approach zero, for
1
379.
are . Substitution of
results in the quadratic equation
, . Hence the general solution, for
, is . The roots Invoking the initial conditions, we obtain the system of equations
________________________________________________________________________
p...
View
Full
Document
This note was uploaded on 03/11/2014 for the course MA 303 taught by Professor Staff during the Spring '08 term at Purdue.
 Spring '08
 Staff

Click to edit the document details