similarly the total force on is 18 taking a clockwise

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: , in which is the displacement of the end of a spring from its equilibrium configuration. Hence, with , the first two springs are in tension, and the last spring is in compression. The sum of the spring forces on is The total force on is ________________________________________________________________________ page 339 —————————————————————————— CHAPTER 7. —— . Similarly, the total force on is . 18 . Taking a clockwise loop around each of the paths, it is easy to see that voltage drops are given by , and . . Consider the right node. The current in is given by . The current leaving the node is . Hence the current passing through the node is Based on Kirchhoff's first law, . . In the capacitor, In the resistor, . In the inductor, . Based on part , . Based on part , It follows that and 20. Let and be the current through the resistors, inductor, and capacitor, respectively. Assign and as the respective voltage drops. Based on Kirchhoff's second law, the net volta...
View Full Document

This note was uploaded on 03/11/2014 for the course MA 303 taught by Professor Staff during the Spring '08 term at Purdue.

Ask a homework question - tutors are online