Sampling_Distribution_(continued)

# A random sample of 1000 people was drawn what was the

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Unformatted text preview: ion of the Sample Proportion Example 5 Election data: Romney versu Obama Suppose on a certain day, the poll showed that Romney had the support of 44% of the voters. A random sample of 1000 people was drawn. What was the probability that the sample would predict a victory for Romney? Find the 95% conﬁdence interval for Romney’s victory ˆ Solution : p = . A victory for Romney means p &gt; .50. Thus P (ˆ &gt; .50) =? p µ (ˆ) = p _________ σ (ˆ) = p ___________ p ∼ Normal (__________,_________) ˆ mean P (ˆ &gt; .50) = P z &gt; .5−sd p = ___________ 95% CI = Sampling Distribution of the Sample Proportion (continued Checkpoint 3 - Modeling and Inference Sampling Distribution of the Sample Proportion Meaning of CI C. Sampling Distribution of the Sample Proportion (continued Checkpoint 3 - Modeling and Inference Sampling Distribution of the Sample Proportion Meaning of CI C. Sampling Distribution of the Sample Proportion (continued Checkpoint 3 - Modeling and Inference Sampling Distribution of...
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## This note was uploaded on 03/12/2014 for the course STATS 10 taught by Professor Ioudina during the Spring '08 term at UCLA.

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