Test2 Answers

470 marks answer this question using the systematic

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: marks] Answer this question using the systematic treatment of equilibrium, clearly stating any approximations you make and then checking them. (a) The pH of a 0.10M solution of acetic acid is 2.88. What is the pKa for acetic acid? (b) What is the pH of a 0.10M solution of sodium acetate (the salt of the conjugate base of acetic acid)? (a) A solution made from FHA=0.10M Charge balance: Mass balance: Plugging into the Ka: You could always make the approximation that since this is an acidic solution you to write the approximate and familiar allowing For this question, though, you already know [H+] from the pH, allowing you to directly calculate And then pKa=4.756. (b) A solution made from FNaA=0.10M A sodium salt is soluble (it does have a solubility limit but throughout this course we have been dealing with dilute solutions well below that solubility limit): The equilibria are Note that this will have to be a basic solution due to the formation of OH-. Charge balance: Mass balance: , Equilibrium constant Substituting into the charge balance and rearranging: Substituting this into the first mass balance: So that We can substitute this directly in the Kb expression Which we could solve through a lot of work, or we could recognize that in the basic solution that will result from the hydrolysis of water, and so we end with the familiar result yielding and and a pH of 8.88. 5. [50 marks] (a)...
View Full Document

This document was uploaded on 03/12/2014 for the course CHM 212 at Rhode Island.

Ask a homework question - tutors are online