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Explain 05 m naoh 05 m hc2h3o2 the following reaction

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Unformatted text preview: occurs: HC2H3O2 + OH- 6 H2O + C2H3O2- Since the strong base exactly neutralizes the weak acid (same concentrations and same volumes), a solution containing a weak base (C2H3O2-) is formed. 0.5 M HCl + 0.2 M NaNO3 NaNO3 is a neutral electrolyte (NO3- is the conjugate base of a strong acid) so it will not react with the strong acid HCl. A strong acid solution is formed. 1.0 M HNO3 + 2.0 M K2CO3 The following reaction occurs: CO32- + H3O+ 6 H2O + HCO3- Only one-half of the CO32- is converted to HCO3- (the CO32- concentration is twice that of the acid), so a CO32-/HCO3- buffer solution is formed....
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This document was uploaded on 03/06/2014 for the course CHEM 102 at CSU Northridge.

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