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Unformatted text preview: an of the data is 8. . The standard deviation is s = 0.271 mV.
Thus, S / N = 1.435/0.271 = 5.3
b) By averaging n measurements, the signal-to-noise ratio improves by /n (see
equation 5.11). To improve S/N from 5.3 (for 8 measurements) to S/N = 10 requires:...
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This document was uploaded on 03/06/2014 for the course CHEM 422 at CSU Northridge.
- Fall '08