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Unformatted text preview: Below: Note:
2) IX. <x> = 0
For Large v, the "Particle" has a High Probability of Being
Found Near the Classical Turning Points. Application to Diatomic Molecules (Assume Bond is a Hookean Spring with Constant k) Classical Potential
V(R) = ½ k (R - Re)2
Classical Kinetic Energy
T = ½ mA vA2 + ½ mB vB2 =
= TCM + ½ We are not interested in the Center-of-Mass motion, only the relative
(vibrational) off the two masses.
Now Define the Angular Frequency According to:
Solve the Harmonic Oscillator Pro...
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