5 to 22 cm away from the lens use ray tracing

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Unformatted text preview: en to represent the retina which can be placed in a range of 1.5 to 2.2 cm away from the lens. Use ray tracing diagrams to support your solutions. a. A corrective lens for nearsightedness with a focal power of -6 diopters is constructed from the material which has an index of refraction of 1.6. In order to see the effect in the eye, calculate the change of image distance when the corrective lens is placed 5 cm in front of the eye model. This distance is not negligible. b. Because the material can also be used in contact lenses, calculate the change in image distance if the distance between the eye model and corrective lens is negligible. Since we are correcting nearsightedness, consider the object being seen as far away from the eye....
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This test prep was uploaded on 03/13/2014 for the course PHYS 1201W taught by Professor Kennethheller during the Fall '13 term at Minnesota.

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