Exam4EquationSheet

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: D = (29.10) BRIDGING, PROBLEM Magnetic Field of a Charged,:Rotating Dielectric Disk (Gauss’s 947 lar 1 uctor, 2 C At t dt way conductionucurrent. Field of a Charged, Rotating Dielectric m Ia 2 law for B fields) the same vz as dvz ¢ C BRIDGING PROBLEM MagneticSThe relationships S 2 Disk d 0 d £ Bpart S (allS increasing a closed atic ular Onaz = betweenqelectric and magnetic fieldsEandl their sources of inducedDuloop movesencla d = - BorS = in axis lim 0 of loop = S S S S dis- A thin dielectric ƒ ¢1tq2with dt = a has a total charge +Sfield)2 on 1B 4. (29.21) B Q it take the charge found in step£3 to make a 1S disk ƒ radius dt 2 E dt F ¢t BQ distribC e assoS 2 3>2 How u2 = does long E dA E can be stated compactly in four (21.2) called second F = A thin dielectric disk with radius a equations,charge + Q distrib- 4. How long P 21it 2 +Ba dS(29.18) i C in step 3 E b make a 2 = found + P d to has a total does x take the chargem0 a l u1 0 uted uniformly over2its surface. It rotates n(Faraday’s law) about (9.5), timestimes complete (9.6) per per second 4pP0 r equations.surface. It rotatesform a second about Ccomplete trip around the rotating ring? Use this0 todtfind the curuted uniformly over its Together they n x around C rotating ring? Use this to encl the Maxwell’s r complete trip S Magnetic-Field Magnitude find the curangu- Point in Magnetic Field S S an axis an axis perpendicular to perpendicular to the surface of the disk disk and passing (Gauss’s of the rotating ring. N l and passing O rent law rotating I (for sely rent of the for mfields) ring. (29.20) multiply these basis of surface of their q S G Induced electricfor Find the an emfthe field at by acenter of S disk. is E and the the relatedAt = vBL center. the When magnetic induced B fields toS the dS 1disk.d £ BUse a result= E 0Section 28.5 oops, E (29.6) E center through its offields: looprelationshipmagnetic field at the centerEof the = - S5. 5. Use aB (29.10) Section 28.5 tolaw981 the displacement from eld, l 1Find 2 through its center. S g the changing£ E + v flux+ a t athe result from (Ampere’sto determine themagnetic field determine including magnetic field magnetic u 1 du = sources. t through (9.11) maI timev dt that this ring produces at the center of by disk. C S S F1 on 2 20 expressions the N) for (conductor S 0zlength Lz S stationary conductor, B i D = P an 0 8.988 * 2field N ofm > uni(29.14) have Distance=r withelectric10 9moves2inC2 there isS dtinduced E B that2 this ring produces at the center of theincreasing dA B 0 rrent S from conductornonelectrostatic = result current) 5 to find S disk. magnetic field q =your result from Sstep(29.19) Bthetotal magnetic field F = qvB FCIntegrate q 6. =6. EIntegrate your pr fromstep 5 find the total form P(constantand v both perpendicu4p B0 field, L ion. SOLUTION GUIDEaGUIDE SOLUTION E 2 S S (displacement current)z only) + .ctly SI origin. This field is nonconservative and cannot be assoIn S r from rings m with r from r = r= from– allall ringsB 0 I radiifrom S = 0 toE£ = a. . lar towith a MasteringPhysics® study areaVideo Video Tutor solution. and to eachstudy area for a for other) BSee potential. (See Example 29.11.)a Tutor solution. + a q (Gauss’s law forwith radii S dr B a ciated fields) hips b See MasteringPhysics® r 29 SUMMARY 29 SUMMARY 0 29 SUMMARY # # 0 ARY # 29 SUMMARY 0 # # # # RY # 0 RY # # # # The table lists magnetic fields caused by several current distributions. In each case the con# # RY # # # # # The table# lists magnetic fields caused by several current distributions. In each case the con# # # # # # e lists magnetic fields caused by several current distributions. In each case the con-...
View Full Document

This document was uploaded on 03/13/2014.

Ask a homework question - tutors are online