Final-solutions 1

# 250 v 0v the electric field between the plates is

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Unformatted text preview: +250 V 0V • The electric field between the plates is directed downward. The force on a negative particle will therefore by upward, so that (b) [5pt] The electric force can be canceled for this specific velocity by turning on a const ant magnetic field, allowing a particle with charge and speed to pass between the plates undeflected. (This device is called a velocity selector.) What is the magnitude and direction of the required magnetic field? so the right-hand rule imples that a magnetic field into the page, in the – direction, will give a downward magnetic force which can cancel the electric field if the magnitude is adjusted correctly. This will occur when so that (c) [5pt] If this magnetic field is constant throughout the entire region surrounding the plates, the electron will follow a curved trajectory after emerging from the velocity selector. Suppose this trajectory has a radius of 29.4 cm. What is the mass of the unknown particle? The particle will follow uniform circular motion with a centripetal force of magnitude so that Solving for the mass gives The particle is a muon, which is similar to an electron, but 200 times heavier, and unstable. 6 6. [15pt] An solenoid contains 640 turns of wire, is 8.00 cm in length, and has a radius of 0.54 cm. (a) [5pt] What is the magnitude and direction of the magnetic field inside the solenoid if the current is A? For the direction, use the coordinate system shown below. The magnetic field points to the left, with magnitude where cm turns per meter. Thus, 8.00 cm 640 turns (b) [5pt] How much energy is in the magnetic field of the solenoid? Alternatively, with giving the same result. (c) [5pt] Suppose a short coil of radius 1.00 cm and 42 turns is wrapped about the center of the solenoid as shown. If the cu...
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## This document was uploaded on 03/09/2014 for the course PHYS 222 at Ohio Northern University.

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