Unformatted text preview: ing
form is = Iα
(c)
is massless and
the
in the
l component I = of = allthemass=ismgL sinbob,
then
mr
mL . So, τ
θ=
mL α. Furthermore, since α = τ /I =
f the bob.
t t θ t t t L t 2 r
T 2 2 at /L, then at =
at = τL
,
I rθ
mg or τL
mgL2 sin θ
=
= g sin θ,
I
mL2 which is the same result we found in part
(a). o the freebody
ess the component of
ent to the circular path nd 2 law to express the Ft = mg sin θ 3 a= Ft = mg sin θ = g sin θ 890 Chapter 9 4. A uniform solid sphere of mass M and radius R is free rotate about a horizontal axis
••
A uniform solid sphere of mass M and radius R is free t
through its center. 77string is wrapped
A
around the sphere and is attached to through its center. A string is wrapped around the s
horizontal axis an
object of mass m. Assume thatto an object of mass m (Figure 958). Assume that the stri
attached the string
does not slip on the sphere. Find
(a) on the sphere. Find (a) the acceleration of the object, and (b) the te
the accelerationstr...
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 Spring '10
 collins
 Physics, Force, Mass, Work, Rotation, mg sin

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