Assignment_4 Solution

Assignment_4 Solution - ELECTRICAL ENGINEERING DEPARTMENT...

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Unformatted text preview: ELECTRICAL ENGINEERING DEPARTMENT California Polytechnic State University BB 255 Assignment #4 Problem #1 . A 1.5 KVA, 220: l 10 V, 60 Hz, single-phase transformer gave the following test results: - Open—circuit test: V = 110 V I = 0.4 A P = 25 W Short-circuit test: V = 8.25 V I = 13.6 A P = 40 W a) Determine the parameters of the approximate equivalent circuit of the transformer referred to the high-voltage side. ' b) Determine the efficiency of the transformer at full-load, 110 V, and 0.8 power factor leading. Use the approximate circuit. Problem #2 A 20 KVA, 2200/220 V, 60 Hz, single—phase transformer gave the following test results: I. Open-circuit test: V = 220 V, I= 1.52 A 7 P = 161 W Short-circuit test: V = 205 V I = 9.1 A P = 465 W a) Determine the parameters of the approximate equivalent circuit of the ‘ transformer referred to the low-voltage side. b) Determine the all-day'efficiency of the transformer on a load cycle supplied at 220 V and approximated by: 95% full load for 8 hours at PF = 0.8 lagging 60% full load for 8 hours at PF = 0.8 lagging 05% full load for 8 hours at PF = 0.8 lagging Problem #3 I A 100 KVA, 11,000/2200 V, 60' Hz, single-phase power system transformer gave the following test results: Open-circuit test: V = 2200 V, I= 1.59 A P = 980 W Short-circuit test: V a 580 V I = 9.1 A P r» 1100 W a) Determine the voltage regulation of the transformer when supplying rated load at 2200 V and a lagging power factor of 0.8. Use the approximate circuit. _ b) Find the efficiency of the transformer when supplying rated load at 0.8 power factor lagging. Problem #4 - The following test data were taken on a 15 KVA, 2200/440 V, 60 Hz transformer: Short-circuit test: P = 620 W t I = 34 A V = 25 V Open-circuit test: P = 320 W I= 1 A V = 440 V a) Calculate the voltage regulation of this transformer when it supplies full load at 0.9 pf lagging. Use the approximate circuit. .b) Find the efficiency at the load condition of part (a). i ,1 l l t l g Problem #5 A lOO-KVA, 11000/2200-V, 60-Hz single-phase transformer has the following equivalent circuit parameters, referred to low—voltage side: Reg = 0.5319, X84 = 2.499, RC = 49509, X”I =14409, The transformer is supplying at 2200-V rated load at a power factor of 0.8 lagging. Use the approximate circuit to determine: 1. The voltage regulation of the transformer, 2. The efficiency of the transformer. ' Problem #6 A IOO—KVA, 60-Hz, 12000/240-V single-phase transformer is tested to obtain the equivalent circuit parameters using a short-circuit test. The voltage applied to the 12000- V side is 600 V with a short—circuit current equal to the rated current and short-circuit power of 1200W. a. Find Reg and Xeq. b. Assume that the transformer supplies a load of 100 KVA at 240 V and 0.95 PF lagging on the secondary side. Determine the voltage required at the primary side and the power factor. Problem #7 A 1.5 KVA, 220:110 V, 60 Hz, single-phase transformer gave the following test results: Open-circuit test: V = 220 V I = 0.2 A P = 25 W Short-circuit test: _ V = 16.5 V I = 6.8 A P = 40 W a. Determine the voltage regulation for full—load at 110 V and 0.85 power factor lagging. Use approximate circuit. b. Determine the efficiency of the transformer at full-load, 110 v, and 0.85 power factor lagging. . - Problem #8 _ A 20 KVA, 2200/220 V, 60 Hz, single-phase transformer gave the following test results: Open-circuit test: . V = 2200 V, I = 0.152 A P = 161 W Short-circuit test: V = 20.5 V I = 91 A P = 465 W a. Determine the voltage regulation of the transformer for a rated load at 220 V and 0.8 pf lagging. Use the approximate circuit. b. Determine the all-day efficiency of the transformer on a load cycle supplied at 220 V and approximated by: ' . full load for 8 hours at PF = 0.8 lagging ,_ 50% full load for 8 hours at PF = 0.8 lagging 05% full load for 8 hours at PF = 0.8 lagging Problem #9 A 100 KVA, 11,000/2200 V, 60 Hz, single-phase power system transformer gave the following test results: Open-circuit test: V = 2200 V, I= 1.59 A ' P = 980 W Short-circuit test: V = 580 V I= 9.1 A P = 1100 _W a) Find the efficiency of the transformer when supplying SOKVA load at 0.8 power factor lagging. 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Assignment_4 Solution - ELECTRICAL ENGINEERING DEPARTMENT...

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