Assignment_6 Solution

Assignment_6 Solution - ELECTRICAL ENGINEERING DEPARTMENT...

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Unformatted text preview: ELECTRICAL ENGINEERING DEPARTMENT California Polytechnic State University BB 255 Assignment #6 Problem #1 . A dc test is performed on a 208-V, Y-connected induction mot0r. Each phase of _ the machine is made of two parallel windings. Ifthe Vdc=9-V and Idczfi-A, what is the resistance of each winding? Problem #2 _ A 220-V, three-phase, 60-Hz induction motor is running at a speed of 1140 rpm. Determine: The number of poles of the machine The speed of the magnetic field The slip of the machine The slip speed P950?“ Problem #3 A 208-V, three-phase, 4-pole, 50-Hz induction motor is running at a slip of 4%. Determine: 1. The speed of the magnetic field 2. The speed of the rotor 3. The slip speed Problem #4 . I A 208—V, three—phase, lZ-pole, 60—Hz induction motor is running at a slip of 4%. Determine: - ‘ 1. The speed of the magnetic field 4. The speed of the rotor 5. The slip speed Problem #5 A 220-V, three-phase, 2-pole, 50-Hz induction motor is running at a slip of 5%._ ' Determine: _ 5. The speed of the magnetic field-in RPM 6. The speed of the rotor in RPM 7. The slip speed of the rotor 8. The rotor frequency in Hz. Problem #6 Answer the questions of problem 5 for a 480-V, three-phase, 4-pole, 60-Hz‘ induction motor running at a slip of 0.035. Problem #7 A three-phase, 4-pole, 60-Hz induction motor is running at a no-load speed of 1790 RPM and a full-load speed of 1720 RPM. Calculate the slip and the ‘ I electrical frequency of the rotor at no«load andfull-load conditions. What is the speed regulation of this motor? Problem #8 A 208—V, three-phase, 2-p01e, 60—‘Hz Y-connected wound rotor induction motor is rated at 15 -hp. Its equivalent circuit components are: R1=0.2 Ohms R2=0.12 OhmsXm=15.0 Ohms X1=0.4l Ohms X2=0.41 Ohms - Pmech=250 W P stray: P coreEO For a slip of 0.05, find: The line current IL The stator copper loss PSCL The air-gap power P AG The converted power PC.mv The induced torque Tind The load torque Thad The overall machine efficiency The motor Speed in RPM and rad/second Fro-rhesus??? Pad No. 937 811E 's Computation Engineer 5’ STAEDTLER® “ Saw/mm j ~ 1 - :- (m) f. (2)09). 33 I ' 2/2.?) @IA u I; gte (din, 27$" ‘ 7 I " 1.19:?“ __ __ 7 " fifidmfi. [as = [Wo- ' Engineer's Computation Pad N0. 937 811E I n; ..= , '_., 39:-..225 . ' " .. ' V " 5 Q51; ' ’ I, - l -_ M f”? I #1 W '= 6 {:7 STAEDTLER® 1 a _'—.r . 7 _' n6 : ‘120 ‘FE ' ::- 02149 [2&9 7' 3.? .5: n5 — m :25».— Iztrc, [9a 614» firm-a: n: mm + (s) e .. _ i::j 3-12” .—-//9a'...g.é_§.¢{0= rpm . .- ' 7 j I: 0.5; 5,: :éfip M. _ Engineer's Computation Pad ® No. 937 811E @STAEDTLER '1 0 I § 2; g 3.5!7'5L5/2éeo/ _= 0.04me =--"'zA/.§"};om . ‘ ® 1 l. (137-: le' '__'=_ "125350 “g 3-”? mm... 2° r 3 ._ , 2., ' Dr .5) IQ; :. [/fipfiggmarzzsq 3.. bkuspé'cd": DJ 9:- Nip" " ' Engineer's Computation Pad N0. 937 811E 4. 92.25;; #405353 :25”? ,1: " 5:3 S'I'REDTLER® . ugévl Halts gag-535,. L. m. ...’20ng :92an W _- fig 445399095) ,7; 7.70m éiézggioizll 52> ‘ , “Web go my i I'Qofihjz-V’Zoxé _' ;-.— ;. 51a, .40 M] ' r is ' _'__ mo 477:» ,0. 05; Engineer‘s Computation Pad N0. 937 811E 5.F,,-'j=-. ; 1896:1725“; 539524. ’ ../g';’<? ‘ - 5:) STA’IIEIIDTLER® m, ‘3'??? 2'3? ’: E P I I": Inuia‘iim 5’14}; GHQ? WERE? ' ‘6 ‘-.3 iii 5 .3 “(minmurn _._.-..—...._—.,_,.... . w. 4......_..... “Mp—- EEZSE_ /[email protected] meat #3: g Qo‘gvj 5aHz‘L, Q—jw/e. ) 544mg, 251,0, age,“ Pm = ~ #:3136414- Q‘ :5.2. .51“ ‘12::6-IZJL )6. 363-9-537- XL 50.3112... 93* @6189 #1;- _ 5.2;, «gins/f C?) IL,th JMI W2 +2399; "III—I 2;“ .::‘ 9.2+ja.q[+ 2.22+J'a.7gj WWW mun,” “mun—u.-_n_mi——.m Lfiak/ I l Engineer's Computation Pad N0. 937 811E é) STfiEDTLEW’ ’ ' I my :‘(Z—ns) V15 :([—¢9-0.5)X5é0 :: 34 20 VP”? wt, 472.2729)" 52;? 3920 Q 1 {O- ' 3 \m Em an.sawmagém m.,m$:_mc..w E. E Em dz m Em Eff-Iiltlwlllflllnlnié. ...
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Assignment_6 Solution - ELECTRICAL ENGINEERING DEPARTMENT...

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