The 1 only remaining possibility is circuit g this

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Unformatted text preview: show that the impedance is finite at all frequencies. The 1 only remaining possibility is circuit (g). This circuit is purely resistive at ω = 0, reduces to R|| j ωC for very small frequencies, and asymptotes to j ω L at sufficiently large frequencies — all of these characteristics are in accordance with the given data. The impedance for circuit (g) is: Z = j ωL + R 1 + j ω CR or R(1 − j ω CR) R CR2 = + j ω (L − ). 2 C 2 R2 2 C 2 R2 1+ω 1+ω 1 + ω 2 C 2 R2 Clearly, R = 1000Ω. It remains to solve for L and C . Use the measured impedance data to write two equations for these unknowns. For example, from the given data, the real part of the impedance is approximately 100Ω at f = 19 MHz. Hence R 100 =...
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