Unformatted text preview: rejection of image responses. 2 28 Solution
a. 58.6, 80, 278.6, 300, 2520, 2541.4, 2878.6, 2900 MHz
b. There would 16 frequencies on the list if there were 4 conversions instead of 3. 3 218 Solution
a. Suppose that the RF input signal is:
sRF (t) = A cos(ωRF t)
The signal at point a is
sa (t) =
=
= sRF (t) cos(ωLO t)
A cos(ωRF t) cos(ωLO t)
1
2 A{cos[(ωRF + ωLO )t] + cos[(ωLO − ωRF )t]} The signal at point b is
sb (t) =
=
= sRF (t) sin(ωLO t)
A cos(ωRF t) sin(ωLO t)
1
2 A{sin[(ωRF + ωLO )t] + sin[(ωLO − ωRF )t]} The signal at point c is
sc (t) = 1
A{− cos[(ωRF + ωLO )t]...
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This homework help was uploaded on 03/13/2014 for the course ECE 453 taught by Professor Staff during the Spring '08 term at University of Illinois, Urbana Champaign.
 Spring '08
 Staff

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